3 -2 0 2 Let V1 = 0 2 , V3= - 6 , and p= 9 Determine if p is in Nul A, where A = V1 v2 V3 3 3 - 9 Is p in Nul A? O A. No, because the augmented matrix | A p is not consistent. O B. No, because Ap is not equal to the zero vector. O C. Yes, because Ap is equal to the zero vector. O D. Yes, because the augmented matrix| A p is consistent