Question: 4 0 3 0 E ) 1 6 0 4 N ? ach followas: O 3 ( g ) = H G ( g )

4030
E)1604N?
ach followas:
O3(g)=HG(g)+CO(g)K=0.106 at 700K
nitially contains 0.0150MH2 and 0.0150MCO2 is allowed to equilibrate at 700
A)[Hb]=0.0226M[CO2] entretions of all substances present?
B)[H6]=0.0113M[CO2]=0.0226M[H2O]=0.00369M[CO]=0.00369M
C)[H6]=0.0113M[CO2]=0.0113M[H2O]=0.00738M[CO]=0.00738M
D)[:[H6]=0.0226M[CO2]=0.01}
(E)[H2]=0.0113M[CO2]=0.0113M[H2O]=0.00738M[CO]=0.00738M
13M[H2O]=0.00369M[CO]=0.00369M
1 Atomic diameter
II. Electron affinity
III. Electronegativity
IV. Atom number
A) Onlv I
 4030 E)1604N? ach followas: O3(g)=HG(g)+CO(g)K=0.106 at 700K nitially contains 0.0150MH2 and

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemistry Questions!