Question: 5 9 % CH . 2 9 5 l = 0 . 4 0 0 m I = 1 0 . 0 A . T

59%
CH.295
l=0.400mI=10.0 A .T?(.)
5 9 % CH . 2 9 5 l = 0 . 4 0 0 m I = 1 0 . 0 A .

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