5. (a) Show using the tables below how the value Oxabcdef12 would be arranged in memory of a little-endian and a big-endian machine. Assume the data are stored starting at address 4 and that the word size is 4 bytes. little endian Big endian address data 0 4 8 12 16 data (6) Show on the following memory the result of the following instruction address 0 4 8 12 16 STURX2, [X0, 8] where X0 = 0x00000010, X2 has the value of 0x000008FF1A2B3D4D. Assume that this is a big endian machine. Address Ox0000000F Ox00000010 Ox00000011 Ox00000012 0x00000013 Ox00000014 Ox00000015 0x00000016 Ox00000017 Ox00000018 Ox00000019 Ox0000001A Ox0000001B Ox0000001C Ox0000001D Ox0000001E Ox0000001F Ox00000020 Ox00000021 Ox00000022 Contents Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 Ox00 OxAA OxBB Ox10 0x2F Ox55 0x44 OxFB (c) Based on the above memory after question (a), what is the result of the LEGv8 instruction "LDUR X1, X3, -8]" if the machine is in little-endian byte orders, where X3 = 0x0000001C. (i.e. what is the value of X1)