s. (a) Show using the tables below how the value 0x1234abcd would be arranged in memory of a little-endian and a big-endian machine. Assume the data are stored starting at address 4 and that the word size is 4 bytes Big endian little endian address data 10 14 Is 12 16 addressdata 12 16 (b) Based on the above memory after question (a), what is the result of the LEGv8 instruction "LDUR XI, [X3, -8)" if the machine is in little-endian byte orders, where X3 = 0x0000001E. (i.e. what is the value of X1). Address Contents Ox0000000F 0:00 0x00000010 000 OX 00000011 XOO00012 ox00000013 Ox00 00000014 Ox00 Ox00000015 200 x00000016 OOD Ox00000017 0200 0x00000018 O200 Ox00000019 O100 Ox0000001A 000 kx0000001B 0200 x0000001C OKAA 00000001DOBA Ox0000001E OXIC 0x0000001F 0x2F Ox00000020 OSS 0x00000021 0x44 Ox00000022 OXFB