5. (a) Show using the tables below how the value 0x1234abcd would be arranged in memory of a little- endian and a big-endian machine. Assume the data are stored starting at address 4 and that the word size is 4 bytes data Big endian address data 0 4 8 12 16 little endian address 0 4 8 12 16 (b) Based on the above memory after question (a), what is the result of the LEGV8 instruction "LDUR X1, [X3, -8)" if the machine is in little-endian byte orders, where X3 = 0x0000001E. (i.e. what is the value of X1). Address Contents Ox0000000F Ox00 Ox00000010 Ox00 Ox00000011 Ox00 0x00000012 Ox00 Ox00000013 Ox00 Ox00000014 Ox00 0x00000015 Ox00 Ox00000016 Ox00 Ox00000017 Ox00 Ox00000018 Ox00 Ox00000019 Ox00 Ox0000001A Ox00 0x0000001B Ox00 0x0000001C OxAA 0x0000001D OxBB Ox0000001E Ox1C Ox0000001F Ox2F Ox00000020 Ox55 Ox00000021 Ox44 Ox00000022 OxFB