$(5$ pts$)5.$ When light of frequency $2\mathrm{.}00$x$1018$ Hz and intensity $0\mathrm{.}0200$ W$/$m$^2$ shines on a certain surface the maximum kinetic energy of the ejected photoelectrons is $2\mathrm{.}00$ eV$.$ What is the maximum kinetic energy of the photoelectrons if the intensity is doubled to $0\mathrm{.}0400$ W$/$m$^2$ and the frequency remains the same? $($a$)2\mathrm{.}00$ eV $(6)3\mathrm{.}00$ eV $($c$)4\mathrm{.}00$ eV $($d$)5\mathrm{.}00$ eV $($e$)6\mathrm{.}00$ eV $($f$)$ none of the above answers