500 Note how far off the front normal force 500 F.J, P1 FL, P2 450 450 Run #10 plate reading was (should read zero) 400 400 40 40 350 350 30 20 300 300 20 Off by = ? N 1pt 10 A Normal Force, Ch P2 (N) 10 A Normal Force, Ch P1 (N) 250 250 A Normal Force, Ch P2 (N) A Normal Force, Ch P1 (N) 0 o 200 200 -10 -10 150 150 -20 -20 100 100 -30 -30 50 50 -40 0 o Note how far off the back friction force 60 40 plate reading was (should read zero) 20 ONA -20 ANON -2 A Parallel Force, Ch P2 (N) A Parallel Force, Ch P2 (N) A Parallel Force, Ch P1 (N) -40 A Parallel Force, Ch P1 (N) -4 -60 -6 -80 -8 Off by = ? N -8 1pt -100 -10 -10 -100 FII, P1 FI|, P2 FI|, P1 FI|, P2 -12 Run #10 -120 -12 -120 -14 Run #10 -14 -140 -140 -16 -16 0.5 1.0 1.5 2.0 2.5 3.0 3.5 3.922 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1 3.922 Time (s) Time (s) [Graph title here] [Graph title here]Take into account how far off the force plates are 500 F.J, P1 F 1, P2 500 450 450 Standing still upright Run #10 Lunge - front foot normal 6pts 400 400 350 350 nfloor = Wbody = N rce, Ch P1 (N) 30 300 250 250 A Normal Force, Ch P2 (N) 200 200 A Normal For nfront = ? N nfront / Wbody= ? 150 ...... 150 100 100 Lunge - Back foot normal 50 50 0 back = ? N nback /Wbody= ? 60 60 Lunge- back foot friction 40 40 20 20 fback = ? N fback / Wbody= ? o 0 -20 -20 A Parallel Force, Ch P1 (N) Parallel Force, Ch P2 (N) -40 -40 -60 -60 -80 .80 -100 FI|. P1 FI|, P2 -100 Lunge- Front foot friction -120 Run #10 -120 ffront = ? N ffront/Wbody= ? -140 -140 0.5 1.0 1.5 2.0 2.5 3.0 3.5 3.922 Time (s) [ Graph title here]Show directions and sizes of surface force components acting on the system, relative to body weight, Wbody Force Equilibrium condition "HHHH HH+ + + + X X X xxxxx EFX = 0 EFV = 0 W body front = ? Wbody Complete back = ? Wbody labels and drag to ffront = ? Wbody vectors fback = ? Wbody 1pt 1111 8pts Drag, orient & resize vectorsEF, = 0 EF = 0 EFup = EFdown EF backward = EFforward Are vertical forces balanced? Are horizontal forces balanced? 1pt Could the uncertainty of the estimations of the average data values be sufficient to 1pt explain any discrepancy?Person is the System EF = 0 500 FL, P1 FL, P2 500 450 450 Force Equilibrium condition - EF. = 0 Standing Run #10 400 400 Only at still points - before and at end of lunge still data 350 350 300 300 250 250 A Normal Force, Ch P2 (N) A Normal Force, Ch P1 (N) 200 200 150 150 100 mitt # # + + + + X X X xxxxx 50 O 60 .... Parallel Force, Ch P2 (N) A Parallel Force, Ch P1 (N) -40 -60 -80 -100 Lunge F||, P1 FI|, P2 -100 -120 still data Run #10 -120 -140 -140 0.5 1.0 1.5 2.0 2. 3.0 3.5 3.922 Time (s) [Graph title here]Compare - relative amounts of normal force on front or back foot to person in lunge 1 - Relative amount of friction to person in lunge 1 lot