6. Correct the following code errors by drawing a line through the erroneous statement and writing...

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6. Correct the following code errors by drawing a line through the erroneous statement and writing a corrected statement on the same line. All versions should print "x^2=169". The only change you can make to the code is the placement of "*" and "&" symbols. No other changes are permitted. Part (a) Part (b) Part (c) void } void } void square (int *p) { *p = *p* *p; } main (void) { int x, *p; P = X; X = 13; void main (void) { int x, *p; X = 13; P = &x; square (&p) printf("x^2=%d\n", x); square (p) printf("x^2=%d\n", x); main (void) { int x; x = 13; square ( *x ) printf("x^2=%d\n", x); 6. Correct the following code errors by drawing a line through the erroneous statement and writing a corrected statement on the same line. All versions should print "x^2=169". The only change you can make to the code is the placement of "*" and "&" symbols. No other changes are permitted. Part (a) Part (b) Part (c) void } void } void square (int *p) { *p = *p* *p; } main (void) { int x, *p; P = X; X = 13; void main (void) { int x, *p; X = 13; P = &x; square (&p) printf("x^2=%d\n", x); square (p) printf("x^2=%d\n", x); main (void) { int x; x = 13; square ( *x ) printf("x^2=%d\n", x);

Answer rating: 100% (QA)

The provided code snippets each contain a few errors in the way pointers are handled with respect to ... View the full answer