7. What is the output of the following code? int *p; int *q; p= new int...

 

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7. What is the output of the following code? int *p; int *q; p= new int [5]; p[0] = 5; for (int i = 1; i < 5; i++) { p[i]= pli - 1] + 2* i; } cout << "Array p: "; for (int i = 0; i < 5; i++) { cout <<p[i] << " "; } cout << endl; q new int [5]; for (int i = 0; i < 5; i++) { q[i] p[4 - i]; } cout << "Array q: "; for (int i = 0; i < 5; i++) { cout < q[1] << " "; } cout <<endl; 7. What is the output of the following code? int *p; int *q; p= new int [5]; p[0] = 5; for (int i = 1; i < 5; i++) { p[i]= pli - 1] + 2* i; } cout << "Array p: "; for (int i = 0; i < 5; i++) { cout <<p[i] << " "; } cout << endl; q new int [5]; for (int i = 0; i < 5; i++) { q[i] p[4 - i]; } cout << "Array q: "; for (int i = 0; i < 5; i++) { cout < q[1] << " "; } cout <<endl;

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The image contains a C code snippet which is intended to print the output of two integer arrays p an... View the full answer