Question: A 1.32 g sample of impure magnesium was analyzed by allowing it to react with excess HCl solution. After of the impure metal was

A 1.32 g sample of impure magnesium was analyzed by allowing it

A 1.32 g sample of impure magnesium was analyzed by allowing it to react with excess HCl solution. After of the impure metal was treated with 100 ml of 0.750 mol/L HCI, the remaining solution required 50 ml of a 0,250 mol/L aqueous sodium hydroxide for complete neutralization. Assuming the impurities do not react with the acid, what is the % by mass of Mg (Mwt 24.3 g/mol) in the sample? Mg + 2 HCI MgCl; + H; Back Titration Problem

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