$[-/8$ Points$]$

Consider the following integral.

${\displaystyle \underset{0}{\overset{1}{}}}\sqrt[3]{17x}dx$

Find a substitution to rewrite the integrand as $\frac{u^{\frac{1}{3}}}{7}du.$

$u=$

$du=()dx$

Indicate how the limits of integration should be adjusted in order to perform the integration with respect to $u.$

$[0,1][]$

Evaluate the given definite integral.

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