Question: 8.29 please! 8.28 A tank is divided into two equal halves by an internal diaphragm. One half contains argon at a pressure of 700 bar

8.29 please! 8.29 please! 8.28 A tank is divided into two equal halves by

8.28 A tank is divided into two equal halves by an internal diaphragm. One half contains argon at a pressure of 700 bar and a temperature of 298 K, and the other chamber is completely evacuated. Suddenly, the diaphragm bursts. Compute the final temperature and the gas in the tank after sufficient time has passed for equilibrium to be attained. Assume that there is no heat transfer between the tank and the gas, and that argon: pressure of (a) Is an ideal gas (b) Obeys the Peng-Robinson equation 8.29 The diaphragm of the preceding problem develops a small leak instead of bursting. If there is no heat transfer between the gas and tank, what is the temperature and pressure of the gas in each tank after the flow stops? Assume that argon obeys the Peng-Robinson equation

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