[9 P] e) Calculate the following enthalpy differences, each based on 1 mol of formula I conversion (FU). Note possible phase transitions. Enter two decimal places: b..h ] = b. he: reaction enthalpy in the standard state b..h 2: Enthalpy difference between the state of the products at the standard temperature and the reaction temperature. b..h3 : enthalpy difference between the state of the reactants at standard temperature and reaction temperature h(TR) with An Then calculate the enthalpy of reaction b..h4 = b. R take the following values. Do not enter any decimal places: - b..h l = -4887 kJ/mol- b.. h2 = 1289 kJ/mol- b..h3 = 1182 kJ/mol Material data: Ib.B h el -250 -200 I Subst ance II kJ/moll kJ/mol K) Fuel (1) Fuel (9) Oxygen 02 (9) Nitrogen N2 (9) Carbon dioxide CO2 (g) Water H20 (0) Water H20 (9) 0 0 -394 -286 -242 0.350 0.250 0.032 0.030 0.043 0.076 0.035 b. 8 he: (standard) enthalpy of formation, cv: isobaric heat capacity. At the present partial pressure of the components holds: Fabric | Ts Ib..h v IK 1 kJ/mol | Fuel 1 323 1 50 | Water H20 | 357 142 Ts: boiling temperature, b.. hv : evaporation enthalpy General notes: All gaseous components are to be considered as ideal gases. The total pressure is equal to the sum of the partial pressures of all components : p =I: Pi k i=1 . Enthalpy changes due to higher pressure (p > Pe) are to be neglected. [9 P] e) Calculate the following enthalpy differences, each based on 1 mol of formula I conversion (FU). Note possible phase transitions. Enter two decimal places: b..h ] = b. he: reaction enthalpy in the standard state b..h 2: Enthalpy difference between the state of the products at the standard temperature and the reaction temperature. b..h3 : enthalpy difference between the state of the reactants at standard temperature and reaction temperature h(TR) with An Then calculate the enthalpy of reaction b..h4 = b. R take the following values. Do not enter any decimal places: - b..h l = -4887 kJ/mol- b.. h2 = 1289 kJ/mol- b..h3 = 1182 kJ/mol Material data: Ib.B h el -250 -200 I Subst ance II kJ/moll kJ/mol K) Fuel (1) Fuel (9) Oxygen 02 (9) Nitrogen N2 (9) Carbon dioxide CO2 (g) Water H20 (0) Water H20 (9) 0 0 -394 -286 -242 0.350 0.250 0.032 0.030 0.043 0.076 0.035 b. 8 he: (standard) enthalpy of formation, cv: isobaric heat capacity. At the present partial pressure of the components holds: Fabric | Ts Ib..h v IK 1 kJ/mol | Fuel 1 323 1 50 | Water H20 | 357 142 Ts: boiling temperature, b.. hv : evaporation enthalpy General notes: All gaseous components are to be considered as ideal gases. The total pressure is equal to the sum of the partial pressures of all components : p =I: Pi k i=1 . Enthalpy changes due to higher pressure (p > Pe) are to be neglected