Question: A 1.05 - kg pole 2.6 meters long is initially situated in a perfectly horizontal position connected to a frictionless pin joint as shown
A 1.05 - kg pole 2.6 meters long is initially situated in a perfectly horizontal position connected to a frictionless pin joint as shown at right. It is released from rest and falls through the final postion where it is perfectly vertical. Consider the pole to be a long, thin rod. a. What is the magnitude of the torque on the pole about Point 0 at the initial position just after being released? b. What is the magnitude of the angular acceleration of the pole at the initial position just after being released? c. What is the magnitude of the tangential acceleration of Point A on the pole at the initial position just after being released? Initial Position Final Position L L/2 A
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a The weight of the pole acts vertically downwards through its center of mass which is located halfway along its length At the initial position this force creates a torque about point O since it has a ... View full answer
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