Question: A 1 6 0 g block hangs from a spring with spring constant ( 1 6 mathrm { ~N } / mathrm

A 160 g block hangs from a spring with spring constant \(16\mathrm{~N}/\mathrm{m}\). At \( t=0\mathrm{~s}\) the block is 19 cm below the equilibrium point and moving upward with a speed of \(140\mathrm{~cm}/\mathrm{s}\).
What is the block's distance from equilibrium when the speed is \(72\mathrm{~cm}/\mathrm{s}\)?
Express your answer with the appropriate units.
View Available Hint(s)
Hint 1. Potential energy
Use the law of conservation of energy. It is more convenient to measure the distance from when determining potential energy. You do not have to consider the gravitational potential
Correct
Part C
What is the block's distance from equilibrium at \( t=3.0\mathrm{~s}\)?
Express your answer with the appropriate units. Enter positive value if the block is above the \(\epsilon \) negative value if the block is below the equilibrium point.
View Available Hint(s)
Hint 1. How to approach the problem
Determine the angular frequency, the amplitude, and the phase constant of the block's oscillation distance as a function of time.
A 1 6 0 g block hangs from a spring with spring

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