Question: A 4th-order linear ODE with constant coefficients has the following homogeneous solutions y1 = 1; y2 = e ; y3 = cos(2x); y4 = sin(2x)

A 4th-order linear ODE with constant coefficients has the following homogeneous solutions y1 = 1; y2 = e ; y3 = cos(2x); y4 = sin(2x) If the right hand side of the ODE is r(x) = 5 + 2sin(2x), what is the form of the particular solution yp? (1) Up = Ax + x [ B cos(2x) + C'sin(2x)] (2) Up = A + Bcos(2x) + C'sin(2x) (3) Up = Ax + Bcos(2x) + Ca sin (2x) (4) Up = Ax + Ba cos(2x) + sin(2x)]
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