Question: = a = a cylindrical outlet surface, as shown in the figure. The depth of the channel in z-direction is W. Air of constant density

 = a = a cylindrical outlet surface, as shown in the

= a = a cylindrical outlet surface, as shown in the figure. The depth of the channel in z-direction is W. Air of constant density p enters the channel with uniform velocity of u U, V = V, where U and V are positive constants. The inlet height is h. The outlet is a quarter cylindrical surface with radius R 2h, and the outlet velocity only has a constant radial component Vr, and no tangential component, that is Ve = 0. The flow field is in steady state. a) (20 pts) Use mass conservation law and integral analysis to compute V, as a function of U, V and h. b) (20 pts) Use momentum conservation law and integral analysis to compute the horizontal force (in x-direction) to anchor the channel in place. (hint: vector integral must be done in rectangular coordinate) A R=2h h

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