Question: a . An implementation using a 4 - to - 1 6 , active high output, decoder has the decoder outputs, 1 . 6 .

a. An implementation using a 4-to-16, active high output, decoder has the decoder outputs, 1.6.7.10,12,13,14,15 linked with an OR gate and the decoder inputis ABCD, where A represents the most signifcant bitb.An implementation using a 4-10-16, active high output, decoder has the decoder outputs, 1.6.7.10,12,13,14,15 linked with a NAND gate and the decoder input is ABCD, where A represents the most signticant bitc. The output can be wrtten as F = ABCD+ABCD-AB CD +ABd. Al of the above are livee. None of the above are truef. a) and c) are both true8. Only a) is true

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