A beam is loaded with a couple moment $M=400N.m$ as shown in figure. If the distance $a=1\mathrm{.}0m$ and the distance $b=3\mathrm{.}0m.$

Part A $-$ By adhering to internal forces sign convention, the internal forces at point $C$ are equal to:

$NC=0N,VC=300N,MC=300N.m$

$NC=0N,VC=-300N,MC=400m$

$NC=0N,VC=-100N,MC=100N*m$

$NC=0N,VC=100N,MC=100N*m$

None of the above