Question: A circle passes through (3, -1) , (-2, 4) , and (6, 8) Using the general form of a circle x2 + y + Dx

A circle passes through (3, -1) , (-2, 4) , and (6, 8) Using the general form of a circle x2 + y + Dx + Ey + F =0 and the points above, fill in missing numbers to create the system of equations. (3, -1) creates D + E + 1F = (-2, 4) creates D + E + 1F = (6, 8) creates D + E + 1F = Solve the system of equations that you created, and write the equation for the circle by filling in the values for D, E, and F. x2 + y- + x+ y+ = 0

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