A compound microscope has a distance D between lenses and an ocular $($eyepiece$)$ with a focal length feye. The magnitude of the total magnification of the microscope is M$.$ The user has a near point distance of N$.$

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Flag question: Question $22$

Question $225$ pts

If the near point distance N$=23\mathrm{.}51$ cm and the eyepiece focal length feye$=7\mathrm{.}24$ mm$,$ what is the eyepiece magnification magnitude?

Enter your answer as a dimensionless, decimal value.$$ For example, if your calculations produce a value of $12\mathrm{.}3,$ enter your answer as $12\mathrm{.}3.$

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Flag question: Question $23$

Question $235$ pts

If the near point distance N$=25\mathrm{.}12$ cm$,$ the eyepiece focal length feye$=3\mathrm{.}24$ mm$,$ the distance between the lenses D$=17\mathrm{.}66$ cm$,$ and the total magnification of the microscope M$=381,$ what is the absolute value of the power of the objective lens?

Enter your answer in units of diopters, inverse meters.$$ For example, if your calculations produce a value of $12\mathrm{.}3$ m$-1,$ enter your answer as $12\mathrm{.}3.$