A computer system has a page size of 1,024 bytes and maintains the page table for...

Transcribed Image Text:

A computer system has a page size of 1,024 bytes and maintains the page table for each process in main memory. The overhead required for doing a lookup in the page table is 500 ns. To reduce this overhead, the computer has a TLB that caches 32 virtual pages to physical frame mappings. A TLB lookup requires 100ns. 1. What TLB hit-rate is required to ensure an average virtual address translation time of 200ns? 2. How many frames are there in the RAM? 3. Ignoring page table overhead and OS needs, how many pages can a process have (max) to be runnable in contiguous memory allocation mode? 4. 5. How many bits are minimally needed for frame numbers of this computer page map tables (PMTs)? Given a 2GB Process what is the size of the Page Map Table (PMT) in bytes and pages if the PMT is flat (one level, assume)? 6. How many PMT levels are needed for the Job of size 16GB? A computer system has a page size of 1,024 bytes and maintains the page table for each process in main memory. The overhead required for doing a lookup in the page table is 500 ns. To reduce this overhead, the computer has a TLB that caches 32 virtual pages to physical frame mappings. A TLB lookup requires 100ns. 1. What TLB hit-rate is required to ensure an average virtual address translation time of 200ns? 2. How many frames are there in the RAM? 3. Ignoring page table overhead and OS needs, how many pages can a process have (max) to be runnable in contiguous memory allocation mode? 4. 5. How many bits are minimally needed for frame numbers of this computer page map tables (PMTs)? Given a 2GB Process what is the size of the Page Map Table (PMT) in bytes and pages if the PMT is flat (one level, assume)? 6. How many PMT levels are needed for the Job of size 16GB?

Answer rating: 100% (QA)

Sure Id be happy to help you with these questions 1 To calculate the TLB hitrate required to ensure an average virtual address translation time of 200... View the full answer