A doubly drained specimen, $2\mathrm{.}53$ cm in height, is consolidated in the lab under an applied stress. The time for $\backslash (44\backslash \%\backslash )$ average consolidation is $10$ min.

$($a$)$ Compute the $\backslash (\backslash$mathrm$\{$c$\}\_\{\backslash$mathrm$\{$v$\}\}\backslash )$ in $\backslash (\backslash$mathrm$\{$cm$\}^\{2\}/\backslash$mathrm$\{$min$\}\backslash )$ value for the lab specimen.

$($b$)$ How long will it take for the specimen to consolidate to an average consolidation of $\backslash (90\backslash \%\backslash )?$ Your answer should be in minutes.

$($c$)$ If the final consolidation settlement of the specimen is expected to be $0\mathrm{.}48$ cm $,$ how long will it take for $0\mathrm{.}384$ cm of settlement to occur? Your answer should be in minutes.

$($d$)$ After $26\mathrm{.}3$ minutes, what percentage consolidation has occurred the middle of the specimen?