A force F = (1.30 N ) i + (5.10 N ) ) + (2.40 N ) k acts on a 7.80 kg mobile object that moves from an initial position of d; = (3.80 m )i + (2.80 m ) ) + (8.30 m ) k to a final position of dy = (3.70 m )i + (2.90 m ) ) + (3.80 m ) k in 3.90 s. Find (a) the work done on the object by the force in the 3.90 s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d ; and d r. (a) Number i Units (b) Number i Units (c) Number i Units v