Question: A force F = ( 5 . 3 0 N ) i + ( 7 . 3 0 N ) j + ( 3 .

A force F =(5.30N)i +(7.30N)j +(3.20N)k acts on a 1.40 kg mobile object that moves from an initial position of d(sub i)=(7.80m)i +(5.20m)j +(7.90m)k to a final position of d(sub f)=(3.30m)i +(4.30m)j +(4.90m)k in 3.60s. Find (a) the work done on the object by the force in the 3.60s interval, (b) the average power due to the force during that interval, and (c) the angle between vectors d (sub i) and d (sub f).

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