Question: A force F = 20 + 10y acts on a particle iny-direction where F is in newton and y inmeter. Work done by this force

A force F = 20 + 10y acts on a particle iny-direction where F is in newton and y inmeter. Work done by this force to move theparticle from y = 0 to y = 1 m is :
(1) 30 J
(2) 5 J
(3) 25 J
(4) 20 J

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Answer Wy1y2Fdy In this case the force FF is given as 2010y2010y and we want to move the par... View full answer

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