A line has slope - and x-intercept -2. Find a vector equation of the line. a. [x, y] = [3, 2] + #[-2, 0] c. [x, y] = [-2, 0] + 1[2, 3] b. [x, )] = [-2, 0] + 1 5. 1 d. [x, )'] = [-2, 0] + #[3, 2] Write the scalar equation of the plane with normal vector 7 = [0, -1, 3] and passing through the point (5, -2, 3). a. y- 3z+ 11 = 0 C. -y+ 32+11 = 0 b. y- 3z- 11 = 0 d. -y+32+16 = 0 In three-space, find the intersection point of the two lines: [x, y, z] = [-1, 2, 0] + /[3, -1, 4] and [x, y, z] = [-6, 8, -1]+12, -5,-31. a. (-1, 2, 0) C. (-4, 3, -4) b. (-6, 8, -1) d. (3, 2, 1)