Question: = A particle is placed at the origin (+2.0, 0.0) with charge 91 +5.0 C and another particle with charge q2 = -3.0 C
= A particle is placed at the origin (+2.0, 0.0) with charge 91 +5.0 C and another particle with charge q2 = -3.0 C is placed at coordinate (+8.0, +8.0). (m) +8 +6 +4 +2 0 i (m) 0 +2 +4 +6 +8 a. Find the magnitude of the electric force on 92 (the negative charge) due to q (the positive charge). b. Find the electric force on 92 (the negative charge) due to q (the positive charge). Note: electric force is a vector, so your answer should be in vector notation.
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To solve this physics problem well use Coulombs Law which gives the electric force F between two cha... View full answer
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