A particle with mass $1\mathrm{.}81103$ kgkg and a charge of $1\mathrm{.}22108$ CC has, at a given instant, a velocity v$=(3\mathrm{.}00104$m$/$s$)$j$^$v$=(3\mathrm{.}00104$m$/$s$)$j$^.$What are the magnitude and direction of the particle$$s acceleration $$produced by a uniform magnetic field B$=(1\mathrm{.}63$T$)$i$^+(0\mathrm{.}980$T$)$j$^$B$=(1\mathrm{.}63$T$)$i$^+(0\mathrm{.}980$T$)$j$^?$

Draw the velocity $$v and magnetic field $$B vectors. Since they have different units, their relative magnitudes aren't relevant. Be certain they have the correct orientations relative to the given coordinate system.