Question: A rectangular microcircuit chip floats on a thin layer of air of constant thickness h , above a porous surface, maintained by air being blown

A rectangular microcircuit chip floats on a thin layer of air of constant thickness h, above a porous surface, maintained by air being blown through the porous surface at speed q. The chip has width b and is sufficiently long in the direction perpendicular to the figure that there is no flow in the z direction. The flow is incompressible and frictional effects may be neglected.
(Take to be the density of the fluid, pa the atmospheric pressure and g the gravitational acceleration.)
We begin by finding an expression for the speed U(x) of the flow in the x direction in the gap under the chip assuming the flow is uniform in the y direction. Consider the conservation of volume in a thin vertical rectangular region of height h lying between x and x+x represented by this sketch:
The mass flux into this fixed region can be written as:
(Clear my choice)
qx+U(x)h-U(x+x)h
qx-U(x)h+U(x+x)h
qx+U(x)h+U(x+x)h
Now U(x+x) can be expanded as
U(x+x)=U(x)+xU'(x)+dots
and so the mass flux into the region can be rewritten as
(Clear my choice)
x(q+U'(x)h)
x(q-U'(x)h)
x(q+U(x))
Now use incompressibility to conclude
(Clear my choice)
q=-U'(x)h
q=U'(x)h
q=-U(x)
Hence, we obtain U(x) by using symmetry to note that U(0)=0 :
U(x)=
A rectangular microcircuit chip floats on a thin

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