A roller coaster car $(471$kg$)$ moves from$$A$(6\mathrm{.}51$m above the ground$)$ to$$B$(22\mathrm{.}0$m above the ground$).$ Two non$-$conservative forces are present: friction does $-3\mathrm{.}00$x $104$J of work on the car, and a chain mechanism does $+4\mathrm{.}46$x $104$J of work to help the car up a long climb. What is the change, in Joules, J$,$ in the car's kinetic energy KEf$-$ KEo$$from$$A$$to$$B$?$ Make sure you get the right sign.