A simple harmonic oscillator's velocity is given by vy(t) = (0.870 m/s)sin(11.2t - 6.25). Find the oscillator's position, velocity, and acceleration at each of the following times. (Include the sign of the value in your answer.) (a) t = 0 position -0.0772 m velocity 0.0947 Your response differs from the correct answer by more than 100%. m/s acceleration 9.686 m/s (b) t = 0.500 s -0.07767 position velocity acceleration Your response differs from the correct answer by more than 10%. Double check your calculations. m 0.00987 The response you submitted has the wrong sign. m/s 9.743 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s t = 2.00 s (c) position velocity acceleration 0.07767 Your response differs from the correct answer by more than 10%. Double check your calculations. m -0.009870 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m/s -9.743 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s