Question: A simple process has four stages A, B, C, and D. The average amount of work needed to process items passing through these stages is

A simple process has four stages A, B, C, and D. The average amount of work needed to process items passing through these stages is as follows: stage A = 68 minutes, stage B = 55 minutes, stage C = 72 minutes, and stage D = 60 minutes. A spotcheck on the work-in-progress between each stage reveals the following: between stages A and B there are 82 items, between stages B and C there are 190 items, and between stages C and D there are 89 items. a. Using Littles law (see Chapter 4), calculate the throughput time of the process. b. What is the throughput efficiency of the process?

In the example above, the operations manager in charge of the process re-allocates the work at each stage to improve the balance of the process. Now each stage has an average of 64minutes of work. Also, the work-in-progress in front of stages B, C, and D is 75, 80, and 82units respectively. How has this changed the throughput efficiency of the process?

Solution for the second part of the question.(In the example above)

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related General Management Questions!