A simple truss supports a force $\backslash ($ F $\backslash )$ at joint A$,$ as shown in the figure below. The force has a magnitude $\backslash ($ F $\backslash )$ and is inclined by an angle $\backslash (\backslash$theta$=10^\{\backslash$circ$\}\backslash )$ from the horizontal. The lengths for all horizontal members is $\backslash ($ s$=3\backslash$mathrm$\{$~m$\}\backslash )$ and for all vertical members is $\backslash ($ h$=5\backslash$mathrm$\{$~m$\}\backslash ).$ The truss is held in equilibrium by a pin at point E and a roller at point F $.$ Using the method of joints, determine the largest applied force $\backslash ($ F$\_\{\backslash$max $\}\backslash )$ so that the force in each truss member does not exceed $\backslash (\backslash$pm $800\backslash$mathrm$\{$kN$\}\backslash ).$

Note: Express tension forces as positive $(+)$ and compression forces as negative $(-).$