A software developer claims the proportion of companies that use JavaScript as their primary software technology is different than $61\%.$ To test this claim, a random sample of $720$ companies is taken and it is determined $460$ of them use JavaScript as their primary software technology.

The following is the setup for this hypothesis test:

H$0$:p$=0\mathrm{.}61$

Ha:p$!=0\mathrm{.}61$

Find the p$-$value for this hypothesis test for a proportion and round your answer to $3$ decimal places. Calculate p$^$ out to $6$ decimal places.

The following table can be utilized which provides areas under the Standard Normal Curve:

z $0\mathrm{.}000\mathrm{.}010\mathrm{.}020\mathrm{.}030\mathrm{.}040\mathrm{.}050\mathrm{.}060\mathrm{.}070\mathrm{.}080\mathrm{.}09$

$1\mathrm{.}50\mathrm{.}9330\mathrm{.}9340\mathrm{.}9360\mathrm{.}9370\mathrm{.}9380\mathrm{.}9390\mathrm{.}9410\mathrm{.}9420\mathrm{.}9430\mathrm{.}944$

$1\mathrm{.}60\mathrm{.}9450\mathrm{.}9460\mathrm{.}9470\mathrm{.}9480\mathrm{.}9490\mathrm{.}9510\mathrm{.}9520\mathrm{.}9530\mathrm{.}9540\mathrm{.}954$

$1\mathrm{.}70\mathrm{.}9550\mathrm{.}9560\mathrm{.}9570\mathrm{.}9580\mathrm{.}9590\mathrm{.}9600\mathrm{.}9610\mathrm{.}9620\mathrm{.}9620\mathrm{.}963$

$1\mathrm{.}80\mathrm{.}9640\mathrm{.}9650\mathrm{.}9660\mathrm{.}9660\mathrm{.}9670\mathrm{.}9680\mathrm{.}9690\mathrm{.}9690\mathrm{.}9700\mathrm{.}971$

$1\mathrm{.}90\mathrm{.}9710\mathrm{.}9720\mathrm{.}9730\mathrm{.}9730\mathrm{.}9740\mathrm{.}9740\mathrm{.}9750\mathrm{.}9760\mathrm{.}9760\mathrm{.}977$

Provide your answer below: