Question: A solution is made by adding 10^(-2.5) M HOCl and 10^(-3) M NaPr to water. Then NaOH is added until the solution pH is 9.

A solution is made by adding 10^(-2.5) M HOCl and 10^(-3) M NaPr to water. Then NaOH is added until the solution pH is 9. How much NaOH must be added in mg/L? Na: 23 g/mole, O: 16 g/mole, H: 1 g/mole .pKa values: 7.60 for HOCl and 4.87 for HPr Please write solution step by step.

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