A tapered bar with a circular cross$-$section is fixed at $x=0$ and an axial force of $0\mathrm{.}3{10}^{6}N$ is applied

at the other end, as shown in Figure $2.$ The length of the bar $(L)$ is $0\mathrm{.}3m,$ and the radius varies as

$r(x)=0\mathrm{.}03-0\mathrm{.}07x,$ where $r$ and $x$ are in meters. Use $E={10}^{10}Pa.$ Assume the displacement in the

form of $u(x)=a_0+a_{1}x+a_2{x}^2.$ Use Rayleigh$-$Ritz Method to solve the problem.