Question: ( a ) . The parameters of a spring mass damper system are m = b = k = 2 units. For a value of

(a). The parameters of a spring mass damper system are m=b=k=2 units. For a value of proportional gain Kp=16 the system becomes critically damped. Find the closed loop stiffness and (4) the corresponding derivative gain Kv for a position regulator system that maintains the position of
(b) The parameters of a spring, mass, damper system are m=b=k=1 unit. Find ,,Kp and Kv for a position regulator control law (employing the partitioned control method) that results in the system being critically damped with a closed loop stiffness of 16.0
Q8. Consider an image ' I ' and
( a ) . The parameters of a spring mass damper

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