Question: A Turing machine M has a useless state if there is some state that is not the accept or reject state such that M never
A Turing machine M has a useless state if there is some state that is not the accept or reject state such that M never enters q. Given an arbitrary TM M, describe how to modify M into machine M1 such that L(M) = L(M1) and M1 does not have any useless states. Modify M into M1 by modifying the TMs definition without removing states from M.
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