A uniform solid ball is set rolling on a track with an initial velocity of $4\mathrm{.}19$ m$/$s$.$ The circular loop of the track has radius r $=0\mathrm{.}42$ m$.$ The lower part of the track is $0\mathrm{.}22$ m below its initial launch height.$$ What is the speed of the ball at the base of the track?$$ Ignore air resistance. Your answer should be in m$/$s$,$ but enter only the numerical part in the box.