A uniform thin rod of mass m = 4.2 kg and length L = 1.4 m can rotate about an axle through its center. Four forces are acting on it as shown in the figure. Their magnitudes are F1 = 2.5 N, F2 = 4.5 N, F3 = 11 N and F4 = 15 N. F2 acts a distance d = 0.11 m from the center of mass.

 

Part (a) Calculate the magnitude 1 of the torque due to force F1, in newton meters. 

 

Part (b) Calculate the magnitude 2 of the torque due to force F2 in newton meters. 

Part (c) Calculate the magnitude 3 of the torque due to force F3 in newton meters. 

Part (d) Calculate the magnitude 4 of the torque due to force F4 in newton meters. 

 

(e) Calculate the angular acceleration  of the thin rod about its center of mass in radians per square second. Let the counter-clockwise direction be positive.

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To calculate the torques and angular acceleration of the thin rod we can use the principles of torque and rotational dynamics Given Mass of the thin rod m 42 kg Length of the thin rod L 14 m Forces ac... View the full answer