A W m by L m hall is to be covered by reinforced concrete slab supported...

 

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A W m by L m hall is to be covered by reinforced concrete slab supported on hinged end portal frames spaced at W/7 on centers as shown by the figure beside. The frame height is 5 m, and no columns are allowed within the hall area. The dead load on the slab is that due to self weight plus 3 kN/m² from roof finishing. The live load on the slab is 4 kN/m². Use f= 28 MPa and fy = 420 MPa for the frames, and fe' = 28 MPa, f, = 280 MPa for other reinforced elements. Use a frame width 400 mm. 1. Show the complete architectural drawings of the hall (plan, elevations, cross-sections, details) 2. Design the one-way slab and the continuous beams. 3. Analyze a typical frame. 4. Design the frame (the girder and the columns. 5. Design the hinge of the frame. 6. Show the complete structural drawings of the hall (plan of the floor, details of continuous beams, details of a typical frame, details of hinges, ....etc.) hs 24 h H 0.40 m Section 1-1 0.40 m 0.50 m Section 2-2 14. Lm Frame Frame Horizontal Section 1+ 1. Lm The Frame 26.1m S Wm 5 m A W m by L m hall is to be covered by reinforced concrete slab supported on hinged end portal frames spaced at W/7 on centers as shown by the figure beside. The frame height is 5 m, and no columns are allowed within the hall area. The dead load on the slab is that due to self weight plus 3 kN/m² from roof finishing. The live load on the slab is 4 kN/m². Use f= 28 MPa and fy = 420 MPa for the frames, and fe' = 28 MPa, f, = 280 MPa for other reinforced elements. Use a frame width 400 mm. 1. Show the complete architectural drawings of the hall (plan, elevations, cross-sections, details) 2. Design the one-way slab and the continuous beams. 3. Analyze a typical frame. 4. Design the frame (the girder and the columns. 5. Design the hinge of the frame. 6. Show the complete structural drawings of the hall (plan of the floor, details of continuous beams, details of a typical frame, details of hinges, ....etc.) hs 24 h H 0.40 m Section 1-1 0.40 m 0.50 m Section 2-2 14. Lm Frame Frame Horizontal Section 1+ 1. Lm The Frame 26.1m S Wm 5 m

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Solution 5 37A0 compression in steel wins A by dd p tenile reinforcement ... View the full answer