A waste gas mixture containing hydrogen sulfide $($HS$)$ is combusted with air, as depicted in Figure below. Analysis of $1\mathrm{.}285$ mol of the exit gas shows $0\mathrm{.}1$ mol of CO$2$ and $0\mathrm{.}08$ mol of SO$2.$ Due to the significant presence of SO$2,$ the flue gas undergoes scrubbing using water. Post$-$scrubbing, the gas composition on a dry basis is $1\mathrm{.}0\%$ CO$,7\mathrm{.}5\%$ CO$2,2\mathrm{.}6\%02,$ and $88\mathrm{.}9\%$ N$2,$ with a moisture content represented by a mole fraction of $1/11.$ The scrubbing solution contains $2\mathrm{.}5\%$ CO$2,8\%$ SO$2,$ and $89\mathrm{.}5\%$ H$20.$Given that the combustion used $10\%$ excess air, determine the composition of the original fuel, expressed in mole fractions or percentages.The main combustion reactions occur within the reactor are as below:CH$4+202+$ CO$2+2$H$20$H$25+3/202-502+$ H$20$Note that there might be other reactions besides the combustion.