Question: A Web server receives requests for web pages at the rate of 88 per second. The standard deviation of these interarrival times is 0.01 second.

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A Web server receives requests for web pages at the rate of 88 per second. The standard deviation of these interarrival times is 0.01 second. On average, the server takes 44 seconds to process web page request. What is the utilization of the server? An Ice cream shop in Queens offers a wide selection of ice cream and frozen yogurt. It has three employees. Assuming that there is unlimited demand. Employee #1 - greets the customer and takes an order 10 minutes per customer. Employee #2 prepares an order-8 min per customer. Employee #3 takes payments 7 min per customer. Each Employee is paid $10 per hour. What is the average labor utilization? A Web server receives requests for web pages at the rate of 88 per second. The standard deviation of these interarrival times is 0.01 second. What is the coefficient of variation of the interarrival process for this server? An Ice cream shop in Queens offers a wide selection of ice cream and frozen yogurt. It has three employees. Assuming that there is unlimited demand. Employee #1 greets the customer and takes an order 10 minutes per customer. Employee #2 prepares an order-8 min per customer. Employee #3 takes payments 7 min per customer. Each Employee is paid $10 per hour. What is the cost of direct labor

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