Activity Duration (weeks) A (start) B C E F (end) 3 2 5 2 3 Precedes Crash Cost/Week B, C E F $370 $120 $240 $160 $400 Suppose that Rafay is only given 9 weeks (instead of 11) to complete the project. By how many weeks should each activity be crashed in order to meet the deadline? Assume that you can crash an activity down to 0 weeks duration. The critical path is A-C - F Activity C is the cheapest on the critical path to crash, so take it to 4 weeks. Now both paths through are critical. What is the cheapest way to crash the project to 9 weeks? Crash C and B by 1 week. What is the total crashing cost? Total cost = Activity C's crash cost + Activity B's crash cost = (2)$240 + (1)$120 = $ (Enter your response as a whole number.)

NOTE: Help me understand where the (2) & (3) comes from in the "total cost" equation near rbe boftom. in the simplest terms please. thanks.

( perfered math explanation than a paragraph)

Suppose that Rafay is only given 9 wooks (instead of 11 ) to complete the project. By how many weeks should each activity be crashed in order to meet the deadline? Assume that you can crash an activity down to 0 weeks duration. The critical path is is the cheapest on the critical path to crash, so take it to 4 weeks. Now both paths through are critical. What is the cheapest way to crash the project to 9 weeks? Crash by 1 week. What is the total crashing cost? Total cost = Activity C's crash cost + Activity B's crash cost =(2)$240+(1)$120=$ (Enter your response as a whole number.)