Question: Activity Predecessor Crash cost (slope) Maximum crash time Normal time Normal cost A - 10 1 4 30 B - 70 2 7 60 C
| Activity | Predecessor | Crash cost (slope) | Maximum crash time | Normal time | Normal cost |
| A | - | 10 | 1 | 4 | 30 |
| B | - | 70 | 2 | 7 | 60 |
| C | A | 0 | 0 | 1 | 80 |
| D | B | 20 | 2 | 4 | 40 |
| E | B | 50 | 3 | 5 | 110 |
| F | C | 200 | 3 | 5 | 90 |
| G | D | 30 | 1 | 2 | 60 |
| H | E | 40 | 1 | 2 | 70 |
| I | F,G,H | 0 | 0 | 2 | 140 |
Consider the following data for a project. Draw the project network. Compute the total direct cost for each project duration. If the indirect costs for each duration are $1,200 for 16 days, $1,130 for 15 days, $1,000 for 14 days, $900 for 13 days, $860 for 12 days, $820 for 11 days and $790 for 10 days, compute the total project cost for each duration. Plot the total direct, indirect, and project costs for each of these durations on a cost-time graph. What is the optimum cost-time schedule for the project?
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
