An analyte $($B$)$ in an aqueous solution is extracted with portions of toluene. If the distribution ratio $(D)$ for analyte $B$ between toluene and water is $11\mathrm{.}6$ and the volume of the aqueous solution containing $B$ is $60c{m}^3,$ what percentage of $B$ will be extracted using the following volumes of toluene?

i$.130c{m}^3$ portion

ii$.310c{m}^3$ portion

$a_n=[\frac{V_x}{D{V}_y+V_x}{]}^n{a}_0$

$a_n=0\mathrm{.}147a_0$:$\mathrm{.}85\mathrm{.}3\%$ extracted

$a_n=0\mathrm{.}0396a_0$:$\mathrm{.}96\mathrm{.}0\%$ extracted