Question: Please show the solution step by step 1. Uranium (VI) can be extracted from aqueous solutions containing nitric acid, A, with ethyl ether, E. As

Please show the solution step by step

1. Uranium (VI) can be extracted from aqueous solutions containing nitric acid, A, with ethyl ether, E. As the aqueous phase contains 1,5 M nitric acid and is saturated with ammonium nitrate, the distribution constant KD = [U(E)]/[U(A)] = 3,5. Calculate the remaining content of uranium(VI) in the water phase and how much U(VI) is extracted, expressed as a % of the total U(VI) amount, under the following conditions

10 ml of 0.0100 M U(VI) is treated with 10 ml of ethyl ether

10 ml of 0.0100 M U(VI) is treated successively with five portions of ethyl ether of 2 ml each

The answer is a) 2.2 mM , 78% b) 0.7 mM , 93%

2. The equilibrium constant for the distribution of a very weak organic acid between ether and water is 1,5. 100 ml aqueous solution of the acid was extracted (shaken to equilibrium) repeatedly with 25 ml ether each time. After each extraction step, the two phases were separated. Calculate the minimum number of extraction steps required for less than 10% of the organic acid to remain in the aqueous phase.

The answer: 8 steps

3. The partition equilibrium constant for the extraction of anisole (C6H5OCH3) from water into an organic solvent is 27 at room temperature.

C6H5OCH3(aq) <-> C6H5OCH3(org)

An aqueous solution contains 100 mg of anisole per liter. What is the minimum volume ratio one must have in an extraction (in one step) to reduce the concentration of anisole in the aqueous solution to 1 mg per liter?

The answer: Vorg/Vaq= 3,67

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