An evaporator is fed continuously with $25t($metric tons$)/$h of a solution consisting of $10$ percent NaOH,$10$ percent NaCl, and $80$ percent $H_{2}O.$ During evaporation, water is boiled off, and salt precipitates as crystals, which are settled and removed from the remaining liquor. The concentrated liquor leaving the evaporator contains $50$ percent NaOH,$2$ percent NaCl, and $48$ percent $H_{2}O.$

Calculate $($a$)$ the kilograms of water evaporated per hour, $($b$)$ the kilograms of salt precipitated per hour, and $($c$)$ the kilograms of concentrated liquor produced per hour.

Answers: $($a$)17,600k\frac{g}{h}$; $($b$)2400k\frac{g}{h}$; $($c$)5000k\frac{g}{h}$